OpGlyph

Fill the operator blanks. Compute left-to-right. Hit the target.

Target
Tap a “?” slot to select it, then press + − × ÷. Press Enter to commit a try.
Tries: 0/6
No brackets • left-to-right
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How OpGlyph works (60 seconds)

Fill the operator blanks, compute left to right, and use feedback to lock the right operators in the right slots.

1) What it is

OpGlyph is a daily operator deduction puzzle. You are given a line of digits with question mark slots between them, plus a target. Your job is to choose the operators for the slots so the whole expression evaluates to the target.

The twist is the rule: there are no parentheses and no normal operator precedence. The calculation always runs left to right. That makes the puzzle feel very different from school arithmetic, and it creates quick little logic moments once you lean into it.

Operators: + − × ÷ No parentheses Compute left to right 6 tries

2) How to play

Tap a question mark slot to select it, then choose an operator: + − × ÷. Fill every slot, then press Enter to commit a try. You can change operators as much as you like before Enter.

When you press Enter, OpGlyph evaluates the expression strictly left to right and checks it against the target. Then you get feedback for each operator slot so you can refine your next attempt.

Digits and target stay fixed Operators are the guess Enter uses one try Clear for a fresh attempt Backspace to edit

3) Feedback legend

Each slot gets Wordle style feedback after you press Enter.

🟩 right operator in the right slot 🟨 operator is used today but in a different slot ⬛ operator is not used in the solution

Play it like a clean deduction loop. Keep greens fixed. Move yellows to new slots. Stop using anything that comes back as not used.

One key rule that matters

OpGlyph always evaluates left to right. Example: 8 ÷ 2 × 5 becomes (8 ÷ 2) = 4, then 4 × 5 = 20. This is why a single operator swap can completely change the outcome.

Example round, step by step

The exact digits change each day, but the solve rhythm stays the same.

Step 1: Get a rough feel for the target

Look at the target and the size of the digits. Ask one simple question. Do you need the value to grow fast, shrink fast, or hover near the same range. That tells you whether you probably need a times early, a divide early, or mostly plus and minus.

Step 2: Make a first clean attempt

Fill every slot and press Enter. Do not wait for perfection. The first attempt is mainly to discover which operators are in the solution at all, and whether any slot is already locked green.

Step 3: Lock greens, relocate yellows

On your next try, keep every green exactly where it is. For yellows, move them into other slots. If you have multiple yellows, swap them around while keeping greens fixed.

Step 4: Eliminate what is not used

If an operator comes back as not used, stop using it. This is the fastest way to reduce noise. Once you are down to two or three possible operators, the remaining placements become much easier.

Step 5: Use the target as a steering wheel

If your result is far above the target, you likely need a divide earlier or a minus where you currently have plus. If you are far below, you likely need a times earlier or a plus where you currently have minus. Small direction checks like this save tries.

Step 6: Finish with one last left to right check

Before your final Enter, read it like the game reads it, left to right. Do a quick mental pass. One slot often stands out as the only place an operator could realistically sit.

Two slot puzzles

With two operator slots, each try is very informative. You can often solve by locking one green, then swapping the other operator into place.

Probe early Swap yellows Keep greens fixed
Four slot puzzles

With four slots, speed comes from elimination. Once you identify an operator that is not used, remove it completely and your next tries get cleaner fast.

Eliminate ⬛ quickly Relocate yellows Aim for fewer changes

Common questions

Why does it ignore normal operator precedence

That rule is the point. Left to right evaluation creates different outcomes and makes the operator placements more interesting to deduce.

What am I actually guessing

The digits and target are locked. You are only guessing which operators appear, and which slot each one belongs in.

What does yellow mean here

Yellow means the operator is part of the solution, but you placed it in the wrong slot. Move it, do not discard it.

If an operator shows not used should I ever use it again

Usually no. Treat it as eliminated unless you have a strong reason to test it again.

How do I get faster at OpGlyph

Do fewer changes per try. Lock greens, relocate yellows, and stop using eliminated operators. Fast wins look calm.

Is it the same puzzle all day

Yes. The digits, target, and solution stay the same for the day, so you can come back later and finish.

Other games you might like

If you enjoy quick deduction with clean rules, try these next.

Play Easy Try Hard

Tip: keep greens fixed, relocate yellows, eliminate anything that is not used.

Made by me 👋

About / Support ☕ Ko-fi

OpGlyph is one of my calm daily brain trainers — tiny rules, quick “aha”, and you feel a bit sharper after a minute or two. One puzzle per day (UTC), three modes, six tries.

Contact: @numberglyph

Quick get-going

Tap a ? slot, choose operators, press Enter. Evaluate left-to-right.

What you’re guessing
  • Digits are locked. You guess the operators.
  • Enter commits one try (6 tries total).
  • Feedback is per-slot: 🟩 right slot, 🟨 wrong slot, ⬛ not used.
Left-to-right rule
No brackets. Example: 8 ÷ 2 × 5 = (8÷2)=4, then 4×5=20.
Tiny strategy
  • Use 🟨 to move an operator to a different slot.
  • If an operator shows ⬛, stop using it.
  • Lock 🟩 first, then shuffle the rest.

🎉 Boom — nice!

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